Maximum sum of hour glass in matrix

Rather than explaining something more in detail, following sample input, output and explanation would help to understand what do we need to do for this problem.

Input:

int[][] input1 = {
    {1, 2, 3, 4, 5},
    {0, 5, 1, 5, 2},
    {0, 0, 0, 1, 3},
    {4, 1, 1, 0, 1},
    {0, 0, 0, 0, 3},
};

Output:
3   4   5
    5
0   1   3

Max Sum for input1 is: 21

Input:
int[][] input2 = {
    {3, 0, 0, 5},
    {2, 5, 5, 5},
    {0, 0, 0, 1},
    {4, 4, 0, 0},
    {0, 0, 3, 0},
};
Output:
2   5   5
    0
4   4   0

Max Sum for input2 is: 20

Input:
int[][] input3 = {
    {-1, -1, 0, -9, -2, -2},
    {-2, -1, -6, -8, -2, -5},
    {-1, -1, -1, -2, -3, -4},
    {-1, -9, -2, -4, -4, -5},
    {-7, -3, -3, -2, -9, -9},
    {-1, -3, -1, -2, -4, -5}
};

Output:
-1   -1   0
    -1
-1   -1   -1

Max Sum for input3 is: -6